a tetrinary gate that only takes in inputs bigger than it equal to 1
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xxnor
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nand gate with two input and one output
(Y' NAND Z) NAND (X' NAND Y) NAND (W NAND Y)
((A * B) + (C * NOT D)) * (NOT A + D)
Let A = a1a0 and B = b1b0 be 2-bit unsigned binary numbers. Design a circuit with inputs a1, a0, b1, b0 and output Fz such that: Fz = 1 if and only if A ≥ B. Draw TWO circuit diagrams: (a) Realize the circuit using only AND2 and OR2 gates, with NOT gates allowed for complemented inputs. (b) Realize the circuit using only NAND2 and NOR2 gates. Clearly label every input, intermediate signal, gate, and final output Fz.
g=A′B′C+AB′C′+A′C′D+AC′D′ draw: Minimum NOR-NOR circuit
g=A′B′C+AB′C′+A′C′D+AC′D′ draw: Minimum NAND-NAND circuit
Design the minimum two-level NAND-NAND and NOR-NOR realizations of: g(A,B,C,D) = Σm(2,3,6,8,9,12) Simplify the Boolean function first using a Karnaugh map. Then draw: Minimum NAND-NAND circuit or Problem 3: $$ g(A,B,C,D)=\Sigma m(2,3,6,8,9,12) $$ Minimum SOP equation for NAND-NAND: g= A B C+A B C + A C D+A C D Use only two logic levels and clearly label all complemented inputs, intermediate outputs, and final output g.
Design the minimum two-level NAND-NAND and NOR-NOR realizations of: g(A,B,C,D) = Σm(2,3,6,8,9,12) Simplify the Boolean function first using a Karnaugh map. Then draw: Minimum NAND-NAND circuit Use only two logic levels and clearly label all complemented inputs, intermediate outputs, and final output g.